Which of the following has the maximum number of atoms?
- A16g of N
2
- B16g of CO
2
- C16g of CH
4
- D16g of O
2
Solution & Step-by-step Explanation
To find the total number of atoms, we use the formula:
Total Atoms=
Molar Mass
Given Mass
×N
A
×Atomicity
Where N
A
is Avogadro's number and atomicity is the number of atoms present in one molecule.
Let's compute this for each option given:
Option A: 16g of N
2
(Molar Mass = 28g/mol, Atomicity = 2)
Atoms=
28
16
×2×N
A
=
28
32
N
A
≈1.14N
A
Option B: 16g of CO
2
(Molar Mass = 44g/mol, Atomicity = 1+2=3)
Atoms=
44
16
×3×N
A
=
44
48
N
A
≈1.09N
A
Option C: 16g of CH
4
(Molar Mass = 16g/mol, Atomicity = 1+4=5)
Atoms=
16
16
×5×N
A
=5N
A
Option D: 16g of O
2
(Molar Mass = 32g/mol, Atomicity = 2)
Atoms=
32
16
×2×N
A
=1N
A
Comparing the calculated coefficients, 16g of CH
4
contains the maximum number of atoms (5N
A
).
Total Atoms=
Molar Mass
Given Mass
×N
A
×Atomicity
Where N
A
is Avogadro's number and atomicity is the number of atoms present in one molecule.
Let's compute this for each option given:
Option A: 16g of N
2
(Molar Mass = 28g/mol, Atomicity = 2)
Atoms=
28
16
×2×N
A
=
28
32
N
A
≈1.14N
A
Option B: 16g of CO
2
(Molar Mass = 44g/mol, Atomicity = 1+2=3)
Atoms=
44
16
×3×N
A
=
44
48
N
A
≈1.09N
A
Option C: 16g of CH
4
(Molar Mass = 16g/mol, Atomicity = 1+4=5)
Atoms=
16
16
×5×N
A
=5N
A
Option D: 16g of O
2
(Molar Mass = 32g/mol, Atomicity = 2)
Atoms=
32
16
×2×N
A
=1N
A
Comparing the calculated coefficients, 16g of CH
4
contains the maximum number of atoms (5N
A
).