Which of the following is the correct order of increasing field strength of ligands to form coordination compounds? - Chemistry MCQ NEET 2020 E1 2026 | ExamTest.live | ExamTest.live

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Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

A $SC N^{-} < F^{-} < C_{2} O_{4}^{2 -} < C N^{-}$
B $SC N^{-} < F^{-} < C N^{-} < C_{2} O_{4}^{2 -}$
C $F^{-} < SC N^{-} < C_{2} O_{4}^{2 -} < C N^{-}$
D $C N^{-} < C_{2} O_{4}^{2 -} < SC N^{-} < F^{-}$

Solution & Step-by-step Explanation

Based on the spectrochemical series, the increasing order of field strength of ligands is: I^{-} < B r^{-} < SC N^{-} < C l^{-} < S^{2} - < F^{-} < O H^{-} < C_{2} O_{4}^{2 -} < H_{2} O < NC S^{-} < e d t a^{4} - < N H_{3} < e n < C N^{-} < CO The correct sequence among options is SC N^{-} < F^{-} < C_{2} O_{4}^{2 -} < C N^{-} .

Practice this question

Try it yourself before checking the explanation above.

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

A

SC N^{-} < F^{-} < C_{2} O_{4}^{2 -} < C N^{-}

B

SC N^{-} < F^{-} < C N^{-} < C_{2} O_{4}^{2 -}

C

F^{-} < SC N^{-} < C_{2} O_{4}^{2 -} < C N^{-}

D

C N^{-} < C_{2} O_{4}^{2 -} < SC N^{-} < F^{-}

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Coordination Compounds Spectrochemical Series

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