Which of the following numbers is perfectly divisible by $11$?

A number is divisible by $11$ if the difference between the sum of its digits at odd positions and the sum of its digits at even positions is either $0$ or a multiple of $11$.Let's test Option B: $57464044$ Sum of digits at odd positions (from right to left: $1^{\text{st}},3^{\text{rd}},5^{\text{th}},7^{\text{th}}$):
$$4+0+6+7=17$$
Sum of digits at even positions ($2^{\text{nd}},4^{\text{th}},6^{\text{th}},8^{\text{th}}$):
$$4+4+4+5=17$$
Difference = $17-17=0$ Since the difference is $0$, $57464044$ is perfectly divisible by $11$.