Which of the following sets of quantum numbers represents the highest energy of an atom?

The energy of an orbital in a multi-electron atom is determined by the $(n+l)$ rule. Higher $(n+l)$ value means higher energy. If $(n+l)$ is the same, the one with higher $n$ has higher energy.$n=3,l=2⟹n+l=5$ ($3d$ orbital)$n=4,l=0⟹n+l=4$ ($4s$ orbital)$n=3,l=0⟹n+l=3$ ($3s$ orbital)$n=3,l=1⟹n+l=4$ ($3p$ orbital)The set with $n=3,l=2$ has the highest $(n+l)$ value (5), so it represents the highest energy.