Which of the two ions from the list given below have the geometry that is explained by the same hybridization of orbitals: ${\text{NO}}_2^{-}$, ${\text{NO}}_3^{-}$, ${\text{NH}}_2^{-}$, ${\text{NH}}_4^{+}$, ${\text{SCN}}^{-}$?

Using VSEPR/Steric Number:${\text{NO}}_2^{-}$: Central N has 5 val. $e^{-}+1$ (charge) $=6$. $2$ used for bonds, $1$ lone pair. Steric no. $=3$ ($s{p}^2$).${\text{NO}}_3^{-}$: Central N has 5 val. $e^{-}+1$ (charge) $=6$. $3$ bonds (double/single resonance). Steric no. $=3$ ($s{p}^2$).${\text{NH}}_2^{-}$: $s{p}^3$.${\text{NH}}_4^{+}$: $s{p}^3$.Both ${\text{NO}}_2^{-}$ and ${\text{NO}}_3^{-}$ have $s{p}^2$ hybridization.