Which one of the following has a regular tetrahedral structure?

* ${\text{BF}}_4^{-}$: Total valence electrons $=3+(7\times 4)+1=32$. Hybrid orbitals $=4$. Hybridization is $s{p}^3$. With zero lone pairs, it has a regular tetrahedral structure.${\text{XeF}}_4$ is square planar.$[\text{Ni}(\text{CN}{)}_4{]}^{2-}$ is square planar.${\text{SF}}_4$ is see-saw.