Which two numbers (not digits of the numbers), from amongst the given options, should be interchanged to make the given equation correct?
12×9+27÷3−5=60
- A27 and 9
- B12 and 3
- C12 and 5
- D5 and 9
Solution & Step-by-step Explanation
Let's evaluate the options to find which swap satisfies the equation by following BODMAS rules:
Test Option A (27 and 9):
The equation becomes:
12×27+9÷3−5
=324+3−5=322
=60
Test Option B (12 and 3):
The equation becomes:
3×9+27÷12−5
This yields a fraction (27/12), so it cannot equal 60.
Test Option C (12 and 5):
The equation becomes:
5×9+27÷3−12
Applying BODMAS:
First, division: 27÷3=9
Next, multiplication: 5×9=45
Substitute back: 45+9−12=54−12=42
=60
CK-12 Foundation
Test Option D (5 and 9):
The equation becomes:
12×5+27÷3−9
Applying BODMAS:
First, division: 27÷3=9
Next, multiplication: 12×5=60
Substitute back: 60+9−9=60
This matches the RHS precisely.
Test Option A (27 and 9):
The equation becomes:
12×27+9÷3−5
=324+3−5=322
=60
Test Option B (12 and 3):
The equation becomes:
3×9+27÷12−5
This yields a fraction (27/12), so it cannot equal 60.
Test Option C (12 and 5):
The equation becomes:
5×9+27÷3−12
Applying BODMAS:
First, division: 27÷3=9
Next, multiplication: 5×9=45
Substitute back: 45+9−12=54−12=42
=60
CK-12 Foundation
Test Option D (5 and 9):
The equation becomes:
12×5+27÷3−9
Applying BODMAS:
First, division: 27÷3=9
Next, multiplication: 12×5=60
Substitute back: 60+9−9=60
This matches the RHS precisely.