Which two numbers (not individual digits) should be interchanged to make the given equation correct?
56+(11×2)−(52÷4)+16=76

Let's check Option D by interchanging 52 and 16:
The equation becomes:

56+(11×2)−(16÷4)+52=76
Applying BODMAS rule:

Brackets and Division/Multiplication:
11×2=22
16÷4=4

Substitute these back into the equation:

56+22−4+52
Addition:

56+22+52=130
Subtraction:

130−4=126
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=76
Let's test Option B by interchanging 56 and 52:
The equation becomes:

52+(11×2)−(56÷4)+16=76
Applying BODMAS rule:

Brackets and Division/Multiplication:
11×2=22
56÷4=14

Substitute values:

52+22−14+16
Addition:

52+22+16=90
Subtraction:

90−14=76
Since LHS=RHS, interchanging 56 and 52 makes the equation correct.