Which two numbers (not individual digits) should be interchanged to make the given equation correct?
$$[(39-3)÷6]+11\times 2-4\times 5=13$$

Let's test the options to see which interchange balances the equation to 13.Test Option C (2 and 5):Interchange 2 and 5 in the equation:
$$[(39-3)÷6]+11\times 5-4\times 2$$
Solving using BODMAS:Inside brackets: $39-3=36$ Division: $36÷6=6$ Substitute back: $6+11\times 5-4\times 2$ Multiplications: $11\times 5=55$ and $4\times 2=8$ Now the expression is: $6+55-8$ Addition/Subtraction: $61-8=53\ne 13$ (Incorrect)Test Option D (3 and 6):Interchange 3 and 6 in the equation:
$$[(39-6)÷3]+11\times 2-4\times 5$$
Solving using BODMAS:Inside brackets: $39-6=33$ Division: $33÷3=11$ Substitute back: $11+11\times 2-4\times 5$ Multiplications: $11\times 2=22$ and $4\times 5=20$ Now the expression is: $11+22-20$ Addition/Subtraction: $33-20=13$ Since $13=13$, interchanging 3 and 6 makes the equation correct.