Which two numbers (not the digits of the numbers), from amongst the given options, should be interchanged to make the given equation correct?
42 ÷ 2 + 13 − 5 × 7 = 9
- A2 and 7
- B42 and 7
- C5 and 7
- D5 and 13
Solution & Step-by-step Explanation
Let's test the options to achieve a final balanced value of 9:
Let's check option A (Interchanging 2 and 7):
The equation becomes:
42÷7+13−5×2
Applying BODMAS:
Division: 42÷7=6
Multiplication: 5×2=10
Evaluate: 6+13−10=19−10=9
Since LHS = RHS = 9, interchanging 2 and 7 makes the equation correct.
Let's check option A (Interchanging 2 and 7):
The equation becomes:
42÷7+13−5×2
Applying BODMAS:
Division: 42÷7=6
Multiplication: 5×2=10
Evaluate: 6+13−10=19−10=9
Since LHS = RHS = 9, interchanging 2 and 7 makes the equation correct.