Which two signs should be interchanged to make the given equation correct?
289+17×12÷216−300=120
- A÷ and +
- B+ and ×
- C÷ and −
- D− and +
Solution & Step-by-step Explanation
Let's test the options using the BODMAS rule to find which interchange balances the equation.
Given equation:
289+17×12÷216−300=120
Test Option A: Interchange ÷ and +
The equation becomes:
289÷17×12+216−300=120
Applying BODMAS:
Division: 289÷17=17
Multiplication: 17×12=204
Addition and Subtraction: 204+216−300=420−300=120
Since LHS=RHS=120, Option A is correct.
Given equation:
289+17×12÷216−300=120
Test Option A: Interchange ÷ and +
The equation becomes:
289÷17×12+216−300=120
Applying BODMAS:
Division: 289÷17=17
Multiplication: 17×12=204
Addition and Subtraction: 204+216−300=420−300=120
Since LHS=RHS=120, Option A is correct.