Binding Energy Questions

Fission of nuclei is possible because the binding energy per nucleon in them :

In the reaction 21H + 31H → 42He + 10n, if the binding energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is :

Assertion: It is not possible to use ${}^{35}\text{Cl}$ as the fuel for fusion energy.Reason: The binding energy of ${}^{35}\text{Cl}$ is too small.

A nucleus has mass represented by $M(A,Z)$. If $M_p$ and $M_n$ denote the mass of proton and neutron respectively and $BE$ the binding energy, then:

If $M(A,Z)$, $M_p$ and $M_n$ denote the masses of the nucleus, proton and neutron respectively and $BE$ represents its binding energy in $MeV$, then:

The mass of a ${}_3^7\text{Li}$ nucleus is $0.042\text{ u}$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of ${}_3^7\text{Li}$ nucleus is nearly:

The Binding energy per nucleon of ${}_3^7\text{Li}$ and ${}_2^4\text{He}$ nuclei are $5.60\text{MeV}$ and $7.06\text{MeV}$, respectively. In the nuclear reaction ${}_3^7\text{Li}{+}_1^1\text{H}\to 2_2^4\text{He}+Q$, the value of energy $Q$ released is: