Capacitors Questions

The plates of a parallel plate capacitor are separated by $d$. Two slabs of different dielectric constant $K_1$ and $K_2$ with thickness $\frac{3}{8}d$ and $\frac{d}{2}$, respectively are inserted in the capacitor. Due to this, the capacitance becomes two times larger than when there is nothing between the plates. If $K_1=1.25K_2$, the value of $K_1$ is:

A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is:

A parallel plate condenser has a uniform electric field $E$ (V/m) in the space between the plates. If the distance between the plates is $d$ (m) and area of each plate is $A$ ($m^2$), the energy (joules) stored in the condenser is:

In an ac circuit an alternating voltage $e=200\sqrt{2}\sin 100t$ volts is connected to capacitor of capacity $1\mu \text{F}$. The r.m.s. value of the current in the circuit is:

Two condensers, one of capacity $C$ and the other of capacity $C/2$ are connected to a $V$ volt battery, as shown. The work done in charging fully both the condensers is:

The energy required to charge a parallel plate condenser of plate separation $d$ and plate area of cross-section $A$ such that the uniform electric field between the plates is $E$, is:

A series combination of $n_1$ capacitors, each of value $C_1$, is charged by a source of potential difference $4V$. When another parallel combination of $n_2$ capacitors, each of value $C_2$, is charged by a source of potential difference $V$, it has the same (total) energy stored in it, as the first combination has. The value of $C_2$, in terms of $C_1$, is then:

A parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and area of each plate is $A$, the energy stored in the capacitor is:

Two thin dielectric slabs of dielectric constants $K_1$ and $K_2$ ($K_1<K_2$) are inserted between plates of a parallel plate capacitor. The variation of electric field '$E$ ' between the plates with distance '$d$ ' as measured from plate $P$ is correctly shown by:

A parallel plate air capacitor has capacity $C$, distance of separation between plates is $d$ and potential difference $V$ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is:

A capacitor of $2\mu \text{F}$ is charged as shown in the diagram. When the switch $S$ is turned to position 2, the percentage of its stored energy dissipated is:

A parallel-plate capacitor of area $A$, separation $d$ and capacitance $C$ is filled with four dielectric materials as shown. If a single dielectric material is to be used to have the same capacitance $C$, then its dielectric constant $k$ is: