Interference Questions

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment is:

In a Young's double slit experiment the intensity at a point where the path difference is $\lambda /6$ ($\lambda$ being the wavelength of the light used) is $I$. If $I_0$ denotes the maximum intensity, $I/I_0$ is equal to:

A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is:

To demonstrate the phenomenon of interference we require two sources which emit radiation of:

A mixture of light, consisting of wavelength $590\text{nm}$ and an unknown wavelength, illuminates Young’s double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the $4^{th}$ bright fringe of the unknown light. From this data, the wavelength of the unknown light is:

In Young's double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If $I_m$ be the maximum intensity, the resultant intensity $I$ when they interfere at phase difference $\varphi$ is given by: