work power energy Questions

An electric lift with a maximum load of $2000\text{kg}$ (lift + passengers) is moving up with a constant speed of $1.5{\text{ms}}^{-1}$. The frictional force opposing the motion is $3000\text{N}$. The minimum power delivered by the motor to the lift in watts is: ($g=10{\text{ms}}^{-2}$)