work Questions

A magnetic needle lying parallel to a magnetic field requires $W$ units of work to turn it through $60^{\circ }$. The torque needed to maintain the needle in this position will be:

A spring of spring constant $5\times 10^3\text{N/m}$ is stretched initially by $5\text{cm}$ from the unstretched position. Then the work required to stretch it further by another $5\text{cm}$ is: