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hardMCQNEET 20192026Chemistry
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For a cell involving one electron E
cell


=0.59V at 298K, the equilibrium constant for the cell reaction is:

  1. A
    1.0×10
    2
  2. B
    1.0×10
    5
  3. C
    1.0×10
    10
  4. D
    1.0×10
    30

Solution & Step-by-step Explanation

The relationship is:
E
cell


=
n
0.059

logK
c


Given E
cell


=0.59V and n=1.

0.59=
1
0.059

logK
c


logK
c

=
0.059
0.59

=10
K
c

=10
10

Practice this question

Try it yourself before checking the explanation above.

For a cell involving one electron E
cell


=0.59V at 298K, the equilibrium constant for the cell reaction is:
A
1.0×10
2
B
1.0×10
5
C
1.0×10
10
D
1.0×10
30

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