For a reaction 1/2A → 2B , the rate of disappearance of ‘A’ is related to the rate of appearance of ‘B’ by the expression: - Chemistry MCQ AIEEE 2026 | ExamTest.live

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For a reaction \frac{1}{2} A \to 2 B, the rate of disappearance of ‘A’ is related to the rate of appearance of ‘B’ by the expression:

Solution & Step-by-step Explanation

For a general reaction a A \to b B, the rate of reaction is given by: Rate = - \frac{1}{a} \frac{d [ A ]}{d t} = \frac{1}{b} \frac{d [ B ]}{d t} Here a = 1/2 and b = 2 . Rate = - \frac{1}{1/2} \frac{d [ A ]}{d t} = \frac{1}{2} \frac{d [ B ]}{d t} - 2 \frac{d [ A ]}{d t} = \frac{1}{2} \frac{d [ B ]}{d t} - \frac{d [ A ]}{d t} = \frac{1}{4} \frac{d [ B ]}{d t}

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For a reaction \frac{1}{2} A \to 2 B, the rate of disappearance of ‘A’ is related to the rate of appearance of ‘B’ by the expression:

- \frac{d [ A ]}{d t} = \frac{1}{2} \frac{d [ B ]}{d t}

- \frac{d [ A ]}{d t} = \frac{1}{4} \frac{d [ B ]}{d t}

- \frac{d [ A ]}{d t} = \frac{d [ B ]}{d t}

- \frac{d [ A ]}{d t} = 4 \frac{d [ B ]}{d t}

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