For reaction aA → xP , when [A] = 2.2 mM , the rate was found to be 2.4 mM s^-1 . On reducing concentration of A to half, the rate changes to 0.6 mM s - Chemistry MCQ Chemistry | ExamTest.live

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For reaction a A \to x P, when [A] = 2.2 mM, the rate was found to be 2.4 mM s^{- 1} . On reducing concentration of A to half, the rate changes to 0.6 mM s^{- 1} . The order of reaction with respect to A is:

A $1.5$
B $2.0$
C $2.5$
D $3.0$

Solution & Step-by-step Explanation

Let the rate law be r = k [A]^{n} .Initially, r_{1} = k [2.2]^{n} = 2.4 ...(i)When concentration is halved, [A]_{2} = 1.1 mM . r_{2} = k [1.1]^{n} = 0.6 ...(ii)Dividing (i) by (ii): \frac{r _{1}}{r _{2}} = \frac{k [ 2.2 ] ^{n}}{k [ 1.1 ] ^{n}} = \frac{2.4}{0.6} 2^{n} = 4 2^{n} = 2^{2} ⟹ n = 2 The order of the reaction is 2.

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For reaction a A \to x P, when [A] = 2.2 mM, the rate was found to be 2.4 mM s^{- 1} . On reducing concentration of A to half, the rate changes to 0.6 mM s^{- 1} . The order of reaction with respect to A is:

1.5

2.0

2.5

3.0

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Chemical Kinetics Order of Reaction Rate Laws

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For reaction $a A \to x P$ , when $[A] = 2.2 mM$ , the rate was found to be $2.4 mM s^{- 1}$ . On reducing concentration of $A$ to half, the rate changes to $0.6 mM s^{- 1}$ . The order of reaction with respect to $A$ is:

Solution & Step-by-step Explanation

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For reaction aA→xP, when [A]=2.2mM, the rate was found to be 2.4mM s−1. On reducing concentration of A to half, the rate changes to 0.6mM s−1. The order of reaction with respect to A is:

Solution & Step-by-step Explanation

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Discussion

For reaction $a A \to x P$ , when $[A] = 2.2 mM$ , the rate was found to be $2.4 mM s^{- 1}$ . On reducing concentration of $A$ to half, the rate changes to $0.6 mM s^{- 1}$ . The order of reaction with respect to $A$ is: