If in a p-n junction diode, a square input signal of $10\text{V}$ is applied as shown
, then the output signal across a load resistance $R_L$ (connected in series with the diode) will be:

A p-n junction diode allows current to flow only when it is forward biased.During the positive half cycle ($+5\text{V}$), the diode is forward biased and conducts. The output voltage across $R_L$ will be $+5\text{V}$ (ignoring barrier potential).During the negative half cycle ($-5\text{V}$), the diode is reverse biased and does not conduct. The output voltage across $R_L$ will be $0\text{V}$.The output signal is a series of pulses reaching $+5\text{V}$.