If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by:
- At=0.693/k
- Bt=6.909/k
- Ct=4.606/k
- Dt=2.303/k
Solution & Step-by-step Explanation
For a first-order reaction:
t=
k
2.303
log
[A]
[A]
0
For 99% completion, [A]=100−99=1% of [A]
0
.
t=
k
2.303
log
1
100
=
k
2.303
log10
2
t=
k
2.303×2
=
k
4.606
t=
k
2.303
log
[A]
[A]
0
For 99% completion, [A]=100−99=1% of [A]
0
.
t=
k
2.303
log
1
100
=
k
2.303
log10
2
t=
k
2.303×2
=
k
4.606