In the combination of logic gates, where inputs A and B are fed into two NAND gates whose outputs are then fed into a third NAND gate, the output Y ca - Physics MCQ NEET (UG) 2018 2026 | ExamTest.live

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In the combination of logic gates, where inputs A and B are fed into two NAND gates whose outputs are then fed into a third NAND gate, the output Y can be written as:

Solution & Step-by-step Explanation

Note: Based on the standard 2018 question diagram.Output of first gate: Y_{1} = \overset{ˉ}{A} .Output of second gate: Y_{2} = \overset{ˉ}{B} .These are fed to a third NAND: Y = \overline{Y_{1} \cdot Y_{2}} = \overline{\overset{ˉ}{A} \cdot \overset{ˉ}{B}} .Using De Morgan's Law: \overline{\overset{ˉ}{A} \cdot \overset{ˉ}{B}} = \overset{ˉ}{\overset{ˉ}{A}} + \overset{ˉ}{\overset{ˉ}{B}} = A + B .This combination acts as an OR gate.

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In the combination of logic gates, where inputs A and B are fed into two NAND gates whose outputs are then fed into a third NAND gate, the output Y can be written as:

\overset{ˉ}{A} \cdot B + A \cdot \overset{ˉ}{B}

A \cdot \overset{ˉ}{B} + \overset{ˉ}{A} \cdot B

\overset{ˉ}{A \cdot B}

A + B

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