In the electrochemical cell: $\text{Zn}|{\text{ZnSO}}_4(0.01\text{M})||{\text{CuSO}}_4(1.0\text{M})|\text{Cu}$, the emf of this Daniel cell is $E_1$. When the concentration of ${\text{ZnSO}}_4$ is changed to $1.0\text{M}$ and that of ${\text{CuSO}}_4$ changed to $0.01\text{M}$, the emf changes to $E_2$. Which of the following is the relationship between $E_1$ and $E_2$? (Given, $\frac{RT}{F}=0.059$)

1. A
   $E_1=E_2$
2. B
   $E_1<E_2$
3. C
   $E_1>E_2$
4. D
   $E_2=0\ne E_1$