In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) for all t is ![image](https://cdn.prepp.in/uploads/production/images/content/2024_05_02/image1_1f2c193b1714638858700.jpg)

The S – domain equivalent circuit is ![image](https://cdn.prepp.in/uploads/production/images/content/2024_05_02/image1_bc0ab1011714638859047.jpg) I≤ft( S ) = {{{V_c≤ft( 0 )}S}}{{1/C_1S + 1/C_2S}} = {V_c≤ft( 0 )}{{≤ft( {1/C_1 + 1/C_2} )}}% MathType!End!2!1! V _c (0) = 12 V I≤ft( S ) = ≤ft( {C_1/C_2{C_1 + C_2}} )≤ft( 12 )% MathType!End!2!1! I(S) = 12 C _eq Taking Inverse Laplace transform for the current in the time domain. i(t) = 12 C _eq δ(t) The above equation shows that it's an impulse.

In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) fo - Electronics and Communication Engineering MCQ PYQs Based test 3: Electric Circuits | ExamTest.live

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In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) for all t is

A $Zero$
B $A step function$
C $An exponentially decaying function$
D $An impulse function$

Solution & Step-by-step Explanation

The S - domain equivalent circuit is I (S) = \frac{\frac{V _{c} ( 0 )}{S}}{\frac{1}{C _{1} S} + \frac{1}{C _{2} S}} = \frac{V _{c} ( 0 )}{( \frac{1}{C _{1}} + \frac{1}{C _{2}} )} V_{c} (0) = 12 V I (S) = (\frac{C _{1} C _{2}}{C _{1} + C _{2}}) (12) I(S) = 12 C_{e q} Taking Inverse Laplace transform for the current in the time domain. i(t) = 12 C_{e q} δ(t) The above equation shows that it's an impulse.

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In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) for all t is

Zero

A step function

An exponentially decaying function

An impulse function

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In the following figure, C₁ and C₂ are ideal capacitors. C₁ has been charged to 12 V before the ideal switch S is closed at t = 0. The current i(t) for all t is

Solution & Step-by-step Explanation

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