In the reaction BrO_3^- (aq) + 5Br^-(aq) + 6H^+ → 3Br_2(l) + 3H_2O(l) . The rate of appearance of bromine ( Br_2 ) is related to rate of disappearance - Chemistry MCQ Chemistry | ExamTest.live | ExamTest.live

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In the reaction BrO_{3}^{-} (a q) + 5 Br^{-} (a q) + 6 H^{+} \to 3 Br_{2} (l) + 3 H_{2} O (l) . The rate of appearance of bromine (Br_{2}) is related to rate of disappearance of bromide ions as following:

A $\frac{d [ Br _{2} ]}{d t} = - \frac{5}{3} \frac{d [ Br ^{-} ]}{d t}$
B $\frac{d [ Br _{2} ]}{d t} = \frac{5}{3} \frac{d [ Br ^{-} ]}{d t}$
C $\frac{d [ Br _{2} ]}{d t} = \frac{3}{5} \frac{d [ Br ^{-} ]}{d t}$
D $\frac{d [ Br _{2} ]}{d t} = - \frac{3}{5} \frac{d [ Br ^{-} ]}{d t}$

Solution & Step-by-step Explanation

From stoichiometry: Rate = - \frac{1}{5} \frac{d [ Br ^{-} ]}{d t} = \frac{1}{3} \frac{d [ Br _{2} ]}{d t} Rearranging for \frac{d [ Br _{2} ]}{d t} : \frac{d [ Br _{2} ]}{d t} = - \frac{3}{5} \frac{d [ Br ^{-} ]}{d t}

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In the reaction BrO_{3}^{-} (a q) + 5 Br^{-} (a q) + 6 H^{+} \to 3 Br_{2} (l) + 3 H_{2} O (l) . The rate of appearance of bromine (Br_{2}) is related to rate of disappearance of bromide ions as following:

A

\frac{d [ Br _{2} ]}{d t} = - \frac{5}{3} \frac{d [ Br ^{-} ]}{d t}

B

\frac{d [ Br _{2} ]}{d t} = \frac{5}{3} \frac{d [ Br ^{-} ]}{d t}

C

\frac{d [ Br _{2} ]}{d t} = \frac{3}{5} \frac{d [ Br ^{-} ]}{d t}

D

\frac{d [ Br _{2} ]}{d t} = - \frac{3}{5} \frac{d [ Br ^{-} ]}{d t}

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Chemical Kinetics Rate Law

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