On electrolysis of dil. sulphuric acid using Platinum (Pt) electrode, the product obtained at anode will be:

In the electrolysis of dilute $H_{2}S{O}_4$:At Cathode: Reduction of $H^{+}$ takes place to produce Hydrogen gas ($H_2$).At Anode: Oxidation of water takes place (preferentially over $S{O}_4^{2-}$) to produce Oxygen gas ($O_2$).Reaction at anode: $2H_{2}O(l)\to O_2(g)+4H^{+}(aq)+4e^{-}$