Resistance of a conductivity cell filled with a 0.1 M solution of an electrolyte is 100 Ω . The conductivity is 1.29 S m^-1 . Resistance of the same c - Chemistry MCQ AIEEE 2006 2026 | ExamTest.live

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Resistance of a conductivity cell filled with a 0.1 M solution of an electrolyte is 100 Ω . The conductivity is 1.29 S m^{- 1} . Resistance of the same cell when filled with 0.2 M of the same solution is 520 Ω . The molar conductivity of 0.2 M solution of the electrolyte will be:

Solution & Step-by-step Explanation

1. Cell Constant (G^{*}): κ = G \cdot G^{*} ⟹ G^{*} = κ \cdot R = 1.29 \times 100 = 129 m^{- 1} .2. Conductivity of 0.2M solution (κ^{'}): κ^{'} = G^{*} / R^{'} = 129/520 = 0.248 S m^{- 1} .3. Molar Conductivity (Λ_{m}): Λ_{m} = \frac{κ}{C} = \frac{0.248 S m ^{- 1}}{0.2 \times 1000 mol m ^{- 3}} = \frac{0.248}{200} = 1.24 \times 1 0^{- 3} S m^{2} mol^{- 1} = 12.4 \times 1 0^{- 4} S m^{2} mol^{- 1}

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Resistance of a conductivity cell filled with a 0.1 M solution of an electrolyte is 100 Ω . The conductivity is 1.29 S m^{- 1} . Resistance of the same cell when filled with 0.2 M of the same solution is 520 Ω . The molar conductivity of 0.2 M solution of the electrolyte will be:

124 \times 1 0^{- 4} S m^{2} mol^{- 1}

1240 \times 1 0^{- 4} S m^{2} mol^{- 1}

1.24 \times 1 0^{- 4} S m^{2} mol^{- 1}

12.4 \times 1 0^{- 4} S m^{2} mol^{- 1}

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