The angular width of the central maximum in the Fraunhofer diffraction for λ = 6000 is θ_0 . When the same slit is illuminated by another monochromati - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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The angular width of the central maximum in the Fraunhofer diffraction for is . When the same slit is illuminated by another monochromatic light, the angular width decreases by . The wavelength of this light is:

Solution & Step-by-step Explanation

The angular width of the central maximum is 2 θ = \frac{2 λ}{a} .So, angular width w \propto λ . \frac{w _{2}}{w _{1}} = \frac{λ _{2}}{λ _{1}} Given w_{2} = w_{1} - 30% w_{1} = 0.7 w_{1} . 0.7 = \frac{λ _{2}}{6000} λ_{2} = 6000 \times 0.7 = 4200 \overset{˚}{A} .

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The angular width of the central maximum in the Fraunhofer diffraction for is . When the same slit is illuminated by another monochromatic light, the angular width decreases by . The wavelength of this light is:

1800 \overset{˚}{A}

4200 \overset{˚}{A}

420 \overset{˚}{A}

6000 \overset{˚}{A}

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