The following mechanism has been proposed for the reaction of NO with Br_2 to form NOBr : NO(g) + Br_2(g) leftharpoons NOBr_2(g) (fast) NOBr_2(g) + NO(g) → 2NOBr(g) (slow) If the second step is the rate determining step, the order of the reaction with respect to NO(g) is:

Rate depends on the slow step: R = k_2 [NOBr_2][NO] .From the first fast equilibrium step: K_eq = [NOBr_2]/[NO][Br_2] [NOBr_2] = K_eq [NO][Br_2] Substitute this into the rate equation: R = k_2 (K_eq [NO][Br_2]) [NO] = k' [NO]^2 [Br_2] The order with respect to NO is 2 .

The following mechanism has been proposed for the reaction of NO with Br_2 to form NOBr : NO(g) + Br_2(g) leftharpoons NOBr_2(g) (fast) NOBr_2(g) + NO - Chemistry MCQ AIEEE 2006 2026 | ExamTest.live

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The following mechanism has been proposed for the reaction of NO with Br_{2} to form NOBr : NO (g) + Br_{2} (g) ⇌ NOBr_{2} (g) (fast) NOBr_{2} (g) + NO (g) \to 2 NOBr (g) (slow) If the second step is the rate determining step, the order of the reaction with respect to NO (g) is:

A $1$
B $0$
C $3$
D $2$

Solution & Step-by-step Explanation

Rate depends on the slow step: R = k_{2} [NOBr_{2}] [NO] .From the first fast equilibrium step: K_{e q} = \frac{[ NOBr _{2} ]}{[ NO ] [ Br _{2} ]} ⟹ [NOBr_{2}] = K_{e q} [NO] [Br_{2}] Substitute this into the rate equation: R = k_{2} (K_{e q} [NO] [Br_{2}]) [NO] = k^{'} [NO]^{2} [Br_{2}] The order with respect to NO is 2 .

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The following mechanism has been proposed for the reaction of NO with Br_{2} to form NOBr : NO (g) + Br_{2} (g) ⇌ NOBr_{2} (g) (fast) NOBr_{2} (g) + NO (g) \to 2 NOBr (g) (slow) If the second step is the rate determining step, the order of the reaction with respect to NO (g) is:

1

0

3

2

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The following mechanism has been proposed for the reaction of $NO$ with $Br_{2}$ to form $NOBr$ : $NO (g) + Br_{2} (g) ⇌ NOBr_{2} (g) (fast)$ $NOBr_{2} (g) + NO (g) \to 2 NOBr (g) (slow)$ If the second step is the rate determining step, the order of the reaction with respect to $NO (g)$ is:

Solution & Step-by-step Explanation

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The following mechanism has been proposed for the reaction of NO with Br2​ to form NOBr:NO(g)+Br2​(g)⇌NOBr2​(g) (fast)NOBr2​(g)+NO(g)→2NOBr(g) (slow) If the second step is the rate determining step, the order of the reaction with respect to NO(g) is:

Solution & Step-by-step Explanation

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The following mechanism has been proposed for the reaction of $NO$ with $Br_{2}$ to form $NOBr$ : $NO (g) + Br_{2} (g) ⇌ NOBr_{2} (g) (fast)$ $NOBr_{2} (g) + NO (g) \to 2 NOBr (g) (slow)$ If the second step is the rate determining step, the order of the reaction with respect to $NO (g)$ is: