The reduction potential of hydrogen half cell will be negative if: - Chemistry MCQ FIITJEE AIEEE 2011 (Set Q) 2026 | ExamTest.live | ExamTest.live

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The reduction potential of hydrogen half cell will be negative if:

A $P (H_{2}) = 1 atm and [H^{+}] = 1.0 M$
B $P (H_{2}) = 2 atm and [H^{+}] = 1.0 M$
C $P (H_{2}) = 2 atm and [H^{+}] = 2.0 M$
D $P (H_{2}) = 1 atm and [H^{+}] = 2.0 M$

Solution & Step-by-step Explanation

For the half reaction 2 H^{+} + 2 e^{-} \to H_{2}, the Nernst equation is: E = E^{\circ} - \frac{0.059}{2} lo g \frac{P ( H _{2} )}{[ H ^{+} ] ^{2}} E = 0 - 0.0295 lo g \frac{P ( H _{2} )}{[ H ^{+} ] ^{2}} For E to be negative, lo g \frac{P ( H _{2} )}{[ H ^{+} ] ^{2}} must be positive.This means \frac{P ( H _{2} )}{[ H ^{+} ] ^{2}} > 1 .Checking options:(1) 1/ 1^{2} = 1 ⟹ E = 0 .(2) 2/ 1^{2} = 2 ⟹ positive log ⟹ E < 0 .(3) 2/ 2^{2} = 0.5 ⟹ negative log ⟹ E > 0 .(4) 1/ 2^{2} = 0.25 ⟹ negative log ⟹ E > 0 .Thus, option B is correct.

Practice this question

Try it yourself before checking the explanation above.

The reduction potential of hydrogen half cell will be negative if:

A

P (H_{2}) = 1 atm and [H^{+}] = 1.0 M

B

P (H_{2}) = 2 atm and [H^{+}] = 1.0 M

C

P (H_{2}) = 2 atm and [H^{+}] = 2.0 M

D

P (H_{2}) = 1 atm and [H^{+}] = 2.0 M

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