The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D_1 and D_2 be the angle of minimum deviation for red and blue ligh - Physics MCQ AIEEE 2006 2026 | ExamTest.live

easyMCQAIEEE 20062026Physics

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The refractive index of glass is for red light and for blue light. Let and be the angle of minimum deviation for red and blue light respectively in a thin prism of this glass. Then:

A $D_{1} > D_{2}$
B $D_{1} < D_{2}$
C $D_{1} = D_{2}$
D $D_{1} can be less than or greater than D_{2} depending upon the angle of prism$

Solution & Step-by-step Explanation

For a thin prism, the angle of minimum deviation is D = (μ - 1) A .Since μ_{b l u e} > μ_{re d} (1.525 > 1.520): D_{b l u e} = (μ_{b l u e} - 1) A D_{re d} = (μ_{re d} - 1) A Clearly, D_{b l u e} > D_{re d}, so D_{2} > D_{1} .

Try it yourself before checking the explanation above.

The refractive index of glass is for red light and for blue light. Let and be the angle of minimum deviation for red and blue light respectively in a thin prism of this glass. Then:

D_{1} > D_{2}

D_{1} < D_{2}

D_{1} = D_{2}

D_{1} can be less than or greater than D_{2} depending upon the angle of prism

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