The surface of a metal is illuminated with the light of 400 nm . The kinetic energy of the ejected photoelectrons was found to be 1.68 eV . The work f - Physics MCQ AIEEE 2009 2026 | ExamTest.live

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The surface of a metal is illuminated with the light of 400 nm . The kinetic energy of the ejected photoelectrons was found to be 1.68 eV . The work function of the metal is (h c = 1240 eV nm):

Solution & Step-by-step Explanation

Using Einstein's photoelectric equation: E_{p h o t o n} = W_{0} + K_{ma x} W_{0} = \frac{h c}{λ} - K_{ma x} W_{0} = \frac{1240 eV nm}{400 nm} - 1.68 eV W_{0} = 3.1 eV - 1.68 eV = 1.42 eV

Try it yourself before checking the explanation above.

The surface of a metal is illuminated with the light of 400 nm . The kinetic energy of the ejected photoelectrons was found to be 1.68 eV . The work function of the metal is (h c = 1240 eV nm):

3.09 eV

1.42 eV

1.51 eV

1.68 eV

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