The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV , and the stopping potential for a radiation incident on this surfac - Physics MCQ AIEEE 2006 2026 | ExamTest.live

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The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV, and the stopping potential for a radiation incident on this surface is 5 V . The incident radiation lies in the:

Solution & Step-by-step Explanation

Einstein's photoelectric equation: E = Φ + K_{ma x} Given Work function Φ = 6.2 eV and K_{ma x} = e V_{s} = 5 eV .Energy of incident photon E = 6.2 + 5 = 11.2 eV .Wavelength λ = \frac{1242}{11.2} \approx 111 nm .Radiation with wavelength in the range 10 nm to 400 nm belongs to the ultra-violet region.

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The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV, and the stopping potential for a radiation incident on this surface is 5 V . The incident radiation lies in the:

X-ray region

ultra-violet region

infra-red region

visible region

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