Two Polaroids P_1 and P_2 are placed with their axis perpendicular. Unpolarised light I_0 is incident on P_1 . A third polaroid P_3 is kept in between - Physics MCQ NEET (UG) 2017 2026 | ExamTest.live

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Two Polaroids P_{1} and P_{2} are placed with their axis perpendicular. Unpolarised light I_{0} is incident on P_{1} . A third polaroid P_{3} is kept in between such that its axis makes 4 5^{\circ} with P_{1} . The intensity of transmitted light through P_{2} is:

Solution & Step-by-step Explanation

After P_{1} : Intensity I_{1} = I_{0} /2 .After P_{3} : Axis is 4 5^{\circ} to P_{1} . I_{3} = I_{1} cos^{2} 4 5^{\circ} = \frac{I _{0}}{2} \times \frac{1}{2} = \frac{I _{0}}{4} .After P_{2} : Axis of P_{2} is perpendicular to P_{1} . Thus, angle between P_{3} and P_{2} is 9 0^{\circ} - 4 5^{\circ} = 4 5^{\circ} . I_{2} = I_{3} cos^{2} 4 5^{\circ} = \frac{I _{0}}{4} \times \frac{1}{2} = \frac{I _{0}}{8} .

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Two Polaroids P_{1} and P_{2} are placed with their axis perpendicular. Unpolarised light I_{0} is incident on P_{1} . A third polaroid P_{3} is kept in between such that its axis makes 4 5^{\circ} with P_{1} . The intensity of transmitted light through P_{2} is:

\frac{I _{0}}{4}

\frac{I _{0}}{8}

\frac{I _{0}}{16}

\frac{I _{0}}{2}

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