Conditional Probability Questions

It is given that the events $A$ and $B$ are such that $P(A)=\frac{1}{4}$, $P(B|A)=\frac{1}{2}$ and $P(A|B)=\frac{2}{3}$. Then $P(B)$ is:

One ticket is selected at random from $50$ tickets numbered $00,01,02,\dots ,49$. Then the probability that the sum of the digits on the selected ticket is $8$, given that the product of these digits is zero, equals:

If $C$ and $D$ are two events such that $C\subset D$ and $P(D)\ne 0$, then the correct statement among the following is:

Three numbers are chosen at random without replacement from $\{1,2,3,\dots ,8\}$. The probability that their minimum is 3, given that their maximum is 6, is: