Solid State Questions

An ionic compound has a unit cell consisting of $A$ ions at the corners of a cube and $B$ ions on the centres of the faces of the cube. The empirical formula for this compound would be:

Total volume of atoms present in a face-centre cubic (FCC) unit cell of a metal is ($r$ is atomic radius):

What type of crystal defect is indicated in the diagram below?
${\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}{\text{Cl}}^{-}$
${\text{Cl}}^{-}\square {\text{Cl}}^{-}{\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}$
${\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}\square {\text{Na}}^{+}{\text{Cl}}^{-}$
${\text{Cl}}^{-}{\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}{\text{Cl}}^{-}{\text{Na}}^{+}$

In a compound, atoms of element $\text{Y}$ form ccp lattice and those of element $\text{X}$ occupy $2/3$ rd of tetrahedral voids. The formula of the compound will be:

Copper crystallizes in fcc with a unit cell length of $361\text{pm}$. What is the radius of copper atom?

The edge length of a face centered cubic cell of an ionic substance is $508\text{pm}$. If the radius of the cation is $110\text{pm}$, the radius of the anion is:

Percentage of free space in cubic close packed structure and in body centred packed structure are respectively:

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is:

Lithium forms body centred cubic structure. The length of the side of its unit cell is $351\text{pm}$. Atomic radius of the lithium will be: