The Thevenin equivalent circuit representation across terminals p-q of the circuit shown in the figure is a

To find Thevenin’s voltage, we need to find open circuit voltage across terminals p, q.



By using voltage division rule,

$V_{th}=4\times \left(\frac{100k}{100k+100k}\right)=2V$

To find Thevenin’s resistance, we need to find equivalent resistance across terminals p, q after removing all independent sources.



R${}_{th\text{­}}$ = (100 k || 100 k) + 100 k

= 50 k + 100 k = 150 kΩ

Now, Thevenin equivalent circuit representation is



The given circuit can be represented by 2 V source in series with 150 kΩ.